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 STAR CALENDAR: The Mystery of the clue.

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nootelepat
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Number of posts : 5
Registration date : 2010-03-17

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PostSubject: STAR CALENDAR: The Mystery of the clue.   STAR CALENDAR: The Mystery of the clue. Icon_minitimeFri Jun 28, 2013 2:31 am

STAR CALENDAR: The Mystery of the clue.

Solar year (365 days, 48 ​​minutes 5:00)
MOON month (during the change of lunar phases) - about 29.5 days.

System of Sun-Earth-Moon system is created with a view toward the observer!

Duration STAR (sidereal) month (the period of revolution of the Moon around the Earth) days before, 27.32.

Duration of the sidereal year (the period of revolution of the Earth around the Sun) STAR 366 days.



10,000 divided by 366 equals 27.32

10000: 366 = 27.32

Here is a random (ha ha, random!) Astronomical COINCIDENCE ...

With direct access to the mathematical decimal system!


So who - all this ASTROmatematiku BUILT??

Great Architect of the Universe??


Sergei Tsimbaljuk

Independent Researcher

https://sites.google.com/site/nootelepat/

so

In fact, moving in its orbit, the Earth makes a full rotation every 365.2564 mean solar days (one sidereal year). But the overall turnover of the vernal equinox, as well as any other point of the celestial sphere (the so-called stellar day, or "24 hours sidereal time") is 23 hours 56 minutes 4 seconds of mean solar time.

In the year sidereal day contains exactly one more than the mean solar.
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